Lithnights
Member
I am trying to figure out how many gallons reside in a 10 foot piece of 1/2" copper pipe.
I have researched and learned that the inside diameter of 1/2" pipe is actually .545 inches.
Thus the radius is .2725 inches
Thus the Area = Pie x r squared... thus 3.14 x .2725 inches x .2725inches = .23 square inches
Thus the Volume = Area x length... thus .23 square inches x 120 inches = 28 cubic inches in 10 foot length
1 cubic foot of water = 7.48 gallons
1 cubic foot = 12x12x12 = 1728 cubic inches
28/1728 = .0162 .0162x7.48 = .12 gallons
So does it sound right that in a 10 foot length of ½†copper, that only .12 (about 1/10) gallons is sitting in there? I checked the math but it still seems a bit low. If so, can you see where my math is incorrect?
Thanks,
I have researched and learned that the inside diameter of 1/2" pipe is actually .545 inches.
Thus the radius is .2725 inches
Thus the Area = Pie x r squared... thus 3.14 x .2725 inches x .2725inches = .23 square inches
Thus the Volume = Area x length... thus .23 square inches x 120 inches = 28 cubic inches in 10 foot length
1 cubic foot of water = 7.48 gallons
1 cubic foot = 12x12x12 = 1728 cubic inches
28/1728 = .0162 .0162x7.48 = .12 gallons
So does it sound right that in a 10 foot length of ½†copper, that only .12 (about 1/10) gallons is sitting in there? I checked the math but it still seems a bit low. If so, can you see where my math is incorrect?
Thanks,