|Posted by hj on February 16, 1999 at 02:55:53:|
|In response to Re: Hot Water Heat|
Yes, but you have to figure in the window area, the amount of exterior wall, whether the area overhead is heated or not, and to a lesser degree the area under the floor. Once you have all these figured out, then you can plug them into the standard heat loss formula and determine the heat requirement. From there you use the radiaton's heat supply at the design water temperature and caluculate the amount of radiation required.
: Is there a formula for the amount of radaitors need for a 15X40 room?
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