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Thread: Question for Ba9s LED Bulb

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  1. #1
    DIY Junior Member nicho's Avatar
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    Default Question for Ba9s LED Bulb

    Hi all,

    I have a LED bulb Ba9S type (130V) which has internally an array of 7 LEDS.

    All the datasheet mention is Voltage:130V AC/DC +10%, Max Current:5,9mA Colour:White clear

    In my circuit the bub is connected directly to a 110V battery and I am trying to add an external resistor to reduce the current into the bulb but before I do that, I would like to figure out the following:

    the array of 7 LEDs in a single bulb are connected in series or parallel?
    The 5.9mA refers to the current of the single LED of the whole array (if in parallel)?
    Can I assume the internal resistor is 21.47kOhm (parallel case, with 3.3V on each diode) or 18.12kOhm (series case)?
    Led Lighting. All roads lead to Rome.

  2. #2
    Plumber jimbo's Avatar
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    Backwards logic. The buls system is rated to operate on 130 volts. You have 110 volts which means you might get 8% less light output than design. WHY would you put a resistor in series or parallel with that to further reduce the voltage and current to the bulb.??

  3. #3
    DIY Senior Member BobL43's Avatar
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    Quote Originally Posted by jimbo View Post
    Backwards logic. The buls system is rated to operate on 130 volts. You have 110 volts which means you might get 8% less light output than design. WHY would you put a resistor in series or parallel with that to further reduce the voltage and current to the bulb.??
    I am sitting on the edge of my chair waiting for the answer to that Jimbo. Thats a pretty small bulb package

    http://www.bulbtown.com/Miniature_Ba...s/322.htmtting


    Last edited by BobL43; 09-20-2012 at 08:06 AM.
    I am definitely not a pro plumber, but I am a pro crastinator

  4. #4
    DIY Junior Member nicho's Avatar
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    Quote Originally Posted by jimbo View Post
    Backwards logic. The buls system is rated to operate on 130 volts. You have 110 volts which means you might get 8% less light output than design. WHY would you put a resistor in series or parallel with that to further reduce the voltage and current to the bulb.??
    OK, thanks, just a experiment
    Led Lighting. All roads lead to Rome.

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    Electrical Contractor/Instructor jwelectric's Avatar
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    In your opinion is this spam?

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    Jack of all trades DonL's Avatar
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    Quote Originally Posted by jwelectric View Post
    In your opinion is this spam?

    Seems a little odd for someone that Advertizes Led Lighting.
    Theory only works perfect in a vacuum.

    Cyber Security Protection for Windows C:\ > WWW.WinForce.Net

  7. #7
    DIY Senior Member BobL43's Avatar
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    Quote Originally Posted by jwelectric View Post
    In your opinion is this spam?
    I don't know. It did not cause me to click on the link to whatever nicho posted. My link was gotten from a quick googling for BA9S 115 volt LED bulbs
    Last edited by BobL43; 09-22-2012 at 10:06 AM.
    I am definitely not a pro plumber, but I am a pro crastinator

  8. #8
    Jack of all trades DonL's Avatar
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    More on a answer to the question on operating LEDs at a higher voltage, They should be in series, and matched very close.

    Many LEDs have a built in resistor, and if they don't it would be kind of silly to use 1 per LED when 1 can be used for all of them if the LEDs are in series.

    LEDs normally short when they burn out, so the remaining ones would have a higher voltage.

    If to many of them short then the resistor may open or the fuse link will open.

    As far as I know a BA9S is the type of bulb base , not a type of bulb.


    I want a 120V battery to experiment with.
    Theory only works perfect in a vacuum.

    Cyber Security Protection for Windows C:\ > WWW.WinForce.Net

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