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Hi all,
I have an electric heater of rating 9.6Kw. Whenever it is switched ON, my electrical meter is running fast and when I switch it OFF the speed of the Electric meter returns back to normal. Y is this so.. Please help... suggest me a procedure to solve this issue by myself... Thanks in advance..![]()
10 KW is a large electric load. More watts than a central air conditioner in cooling mode, more than a clothes dryer, about the same as a stove with a four burners and the oven running!!! The speed of a meter tells you how fast the $$$$$$$$$ is being sucked out of your wallet!!!!
The "procedure" to stop this issue is simple, DON'T turn on the heater. The meter is recording electrical usage and that heater, whatever it is, is using a LOT of it.
That has to be a joke.
The Weather in saudi arabia is around 100 Degrees today.
Why would the heater be on ? I would turn it off, and turn on the air conditioner, And see how fast the meter spins.
Have a great Day.
DonL
Don't pay someone to do a job fast, when you can do a half-fast job yourself.
Well First of us thanks for the replies ppl ova here....
This is not a joke for me..lol.. We had installed the similar Heaters at different locations and didn't have any complaints.
Maybe that one is wired incorrectly, or could be operating at around 10 KW, about normal.
You can always determine the usage by;
The amount of energy represented by one revolution of the disc is denoted by the symbol Kh which is given in units of watt-hours per revolution. The value 7.2 is commonly seen. Using the value of Kh, one can determine their power consumption at any given time by timing the disc with a stopwatch. If the time in seconds taken by the disc to complete one revolution is t, then the power in watts is P = 3600 * Kh Divided by t in seconds. For example, if Kh = 7.2, as above, and one revolution took place in 14.4 seconds, the power is 1800 watts. This method can be used to determine the power consumption of household devices by switching them on one by one.
Good Luck on your project.
DonL
P.S. That calculation is based on a 60 HZ system, Adjust the formula for your AC operating Frequency.
Last edited by DonL; 05-15-2011 at 11:01 AM. Reason: P.S.
Don't pay someone to do a job fast, when you can do a half-fast job yourself.
I am guessing that at 9.6 kw the rotation of the disc might be a bit hard to time.
@ DonL
Well Thanks for superb calculation method....Can u please little elaborate on the formula how did u derive that for a 60Hz operating frequency....
If there is incorrect wiring...How to rectify the issue?... Do we need to check the whole wiring in the house or How...? As far when we checked the current drawn by the heating element its normal and the value is as per standards.
Last edited by shahnaimath; 05-15-2011 at 10:46 PM.
Which voltage system do you have?
Is it a single phase 127 volt or 220 volt?
Nearly 10Kw is a large load! The meter would run much faster when it is on. That's like 100 100W light bulbs all on at the same time. Often, another means of heating is less expensive, but not always. Natural gas or propane or oil in a furnace may be more ecconomical, but maybe not as neat, and then, you'd have to pay for installation and have those as energy options. Not much you can do about it other than tighten the building up to seal leaks, add insulation, and then live with the result.
Jim DeBruycker
Important note - I'm not a pro
Retired Defense Industry Engineer
quote; 220 Volt two phase.
Actually 220 volt SINGLE phase. Check the amp draw of the heater, the main lines with and without the heater, and then you will know if the wiring is correct or not.
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